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The threat is not sufficent to involve the police
I have located the IP address from the header (I think)
and would like to identify the name of the person who sent it
and if possible that persons phone number and address.
Using the web I located the area from where it was sent. Here is the header:

Received: from smtpout.mac.com ([17.250.248.182])
by mail.wordpix.com (Merak 7.4.5) with SMTP id JEA74702
for ****; Fri, 19 Jan 2007 15:31:32 -0800

Received: from mac.com (smtpin07-en2 [10.13.10.152])

by smtpout.mac.com (Xserve/8.12.11/smtpout12/MantshX 4.0) with ESMTP id l0JNVRhb019670

for *** Fri, 19 Jan 2007 15:31:29 -0800 (PST)

Received: from [192.168.1.46] (pool-71-109-217-177.lsanca.dsl-w.verizon.net [71.109.217.177])

(authenticated bits=0)

by mac.com (Xserve/smtpin07/MantshX 4.0) with ESMTP id l0JNVLIh013372;

Fri, 19 Jan 2007 15:31:22 -0800 (PST)
Message-Id:

2007-02-01 08:42:40 · 3 answers · asked by lapaul 2 in Computers & Internet Security

3 answers

The only way to do it Is getting court order ones you get it call service provider.

2007-02-01 08:48:02 · answer #1 · answered by Anonymous · 0 0

First contact the web admins of the server that the mail was sent from.
Although it isn't "big" enough for the police to get behind you, the threat should be enough for the server's admin to look up the email data. He/She should be able to get the person's info, emails sent, etc...
Make sure that you are patient. Take one step at a time.

I can assist you
knvb1123[at]gmail[dotcom]

2007-02-01 10:19:49 · answer #2 · answered by knvb1123 2 · 1 0

Here's a reverse IP/domain look-up tool:

2007-02-01 08:47:46 · answer #3 · answered by xwdguy 6 · 0 0

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