2007-02-01 06:43:15 · 14 answers · asked by Anonymous in Entertainment & Music ➔ Celebrities
LOL, I've had this debate with my friends in the past. We finally decided on Eva Mendez. Her facial features are more striking. She has very sultry eyes and a very sexy mole on her face. Her lips and smile are more beautiful too. Eva Longoria is way more stylish though. She never misses a beat on the red carpet and her hair is always perfect. Oh, not to mention that Eva Longoria has the hotter boyfriend, or should I say fiance:)
2007-02-01 07:24:22 · answer #1 · answered by Betty 2 · 0⤊ 0⤋
Eva Mendes
2007-02-01 07:37:33 · answer #2 · answered by David 6 · 1⤊ 0⤋
Ummm that's a toughie I guess Eva Mendez I don't know she just has something that makes her sexier then Eva Longoria. Eva Mendez has like an exotic look to her Eva Longoria even though she is hispanic she just doesn't have that sexy exotic look Mendez has. So Eva Mendez is prettier. I guess it wasn't that hard to pick which one of the Eva's is prettier after all lol.
2007-02-01 07:31:15 · answer #3 · answered by mari 2 · 1⤊ 0⤋
I think Eva Mendez is prettier, Ava Longoria looks like a bug.
2007-02-01 06:51:44 · answer #4 · answered by R♥bin 4 · 1⤊ 0⤋
eva longoria 4 sure
2007-02-02 15:27:16 · answer #5 · answered by malky132000 2 · 1⤊ 0⤋
eva longoria is prettie.
i really love her face and her body.
i like her acting in desperate housewives and it is really good. i think they are both beatiful sooooo much but ewva longoria is a little bit prettier !!!
2007-02-01 07:29:54 · answer #6 · answered by Okano-Irl 5 · 1⤊ 0⤋
eva longoria
2007-02-01 07:55:42 · answer #7 · answered by killhandekill 2 · 1⤊ 0⤋
That's a tough one, but if forced to choose, I would have to say that Longoria is "very cute" and Mendes is "very hot".
2007-02-01 07:27:57 · answer #8 · answered by Anonymous · 1⤊ 0⤋
"Eva the Diva" from America's Next Top model
2007-02-01 07:08:30 · answer #9 · answered by Sue Sue2 3 · 1⤊ 0⤋
Eva Mendez. More sex appeal.
2007-02-01 11:04:46 · answer #10 · answered by Bunnytoes:) 3 · 1⤊ 0⤋