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a. A car climbs a steep hill with its speed dropping from 60 km/h at the bottom to 15 km/h at the top
b. A car climbs a steep hill and goes over the crest and down on the other side, all at the same sped of 40 km/h
c. A car climbs a steep hill at the constant speed of 40 km/h
d. A car turns a corner at the constant speed of 20 km/h

2007-02-01 06:36:50 · 8 answers · asked by kacwccj 3 in Science & Mathematics Physics

8 answers

The only case listed in your choices which the car is not accelerating is choice "c".

a) The car is clearly accelerating because the speed of the car is changing in time (starts out at 60 km/h, ends up at 15 km/h).

b) The car is again accelerating; this time because of the direction of its velocity is changing even though the speed is constant.

d) The car's direction is changing as it goes around the corner, thus the car is accelerating even if its speed is constant.


Choice c) The car's speed and direction are constant, the car is not accelerating.

2007-02-01 06:57:59 · answer #1 · answered by mrjeffy321 7 · 0 0

Acceleration means a change in velocity. Look at all the examples. In which one can you represent the velocity vector with just a single straight line of constant magnitude? In a), the magnitude changes from beginning to end; in b), it changes direction at the top of the hill; in d), it constantly changes direction as the car rounds the curve. Only in c) is the velocity vector unchanged in both magnitude and direction.

2007-02-01 06:58:22 · answer #2 · answered by Grizzly B 3 · 0 0

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2016-11-23 20:49:01 · answer #3 · answered by ? 3 · 0 0

I suppose b

2007-02-01 06:43:11 · answer #4 · answered by maussy 7 · 0 0

A

2007-02-01 06:44:53 · answer #5 · answered by David B 5 · 0 0

d and b and c

2007-02-01 07:30:05 · answer #6 · answered by deas 1 · 0 0

C

2007-02-01 06:40:21 · answer #7 · answered by ian_eadgbe 3 · 0 0

c.

2007-02-01 06:48:25 · answer #8 · answered by raj 7 · 0 0

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