Yes, one ange would be arctan(10/4)=68.2 degrees, the other would be 21.8 degrees.
2007-02-01 05:05:26
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answer #1
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answered by bruinfan 7
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Let two unknown angle be A and C
and angle B = 90
let a = 4,
b = 10
therefore c = sqare root of (116)
c = 10.77
Cos A = {(b^2 + c^2 - a^)/2*b*c}
similarly you can calculate Cos B also.
Taking inverse of these you will get value of angle A and B
I hope it will help.
2007-02-01 13:19:08
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answer #2
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answered by Laeeq 2
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you can figure out your lengths and angles by using two methods, law of sines or law of cosines. you can figure out the third length by using the pythagothem theorem (sp?) which is a^2 + b^2 = c^2. Of course that is really a simplified version of the law of cosines.
as to what is the law of cosines? a^2 = b^2 + c^2 + 2*b*c* cos A
and the law of sines? sin A / a = sin B / b = sin C / c
so in your situation... let a = 10, b = 4, C = 90, and find c, A, and B
2007-02-01 13:07:36
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answer #3
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answered by Rularn 2
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The hypotenuse could be figured using Pythagoras, but is not needed for this problem. The angles are the arctangents of 0.4 and 2.5. (Why?) They can be determined from tables or using a scientific calculator.
2007-02-01 13:03:50
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answer #4
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answered by Anonymous
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Take the tan 10/4 , which will give you one of the internal angles. Then take the tan 4/10 , which gives you the other internal angle.
And by tan, I mean tangent (such as sine, cosine, tangent).
Have a great day!
2007-02-01 13:03:26
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answer #5
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answered by Sam M 2
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should be 30 & 60 degrees each, yes?
2007-02-01 13:08:18
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answer #6
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answered by stretch 7
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just remember this:
SohCahToa
what does that mean ??
S = sin = opposite / hypotenuse
C = cos = adjacent / hypotenuse
T = tan = opposite / adjacent
2007-02-01 13:05:12
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answer #7
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answered by sk_1808 1
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You should probably do it or you'll screw it up when it shows up on your next test. You won't learn anything by having some one else do it for you.
2007-02-01 13:02:04
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answer #8
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answered by Gene 7
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