What was the change in the potential energy of the system?
2007-02-01 04:52:13 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The change in the Potential Energy is equal to the final Potential Energy minus the intiial Potential Energy.
We are talking about gravitational Potential Energy here, so,
PE = mgh
Where mg is the weight of the object and h is the height of the object above the zero potential (the "floor").
Final PE - Initial PE = mg(final height) – mg(initial height)
ΔPE = mg(Δh),
where Δh is the change in height, Δh = final height - initial height.
ΔPE = (12.0 Newtons) * (2.15 m -0.75 m)
ΔPE = (12.0 N) * (1.40 m)
ΔPE = 16.8 Joules
2007-02-01 04:59:30 · answer #1 · answered by mrjeffy321 7 · 0⤊ 0⤋
PE on table = force x height = 12.0N x 0.75m = 8.0J
PE on shelf = force x height = 12.0N x 2.15m = 25.8J
Difference between them = 25.8J - 8.0J = 17.8J
2007-02-01 04:58:09 · answer #2 · answered by swisshorizon 2 · 0⤊ 0⤋
12x2.15 - 12x.75 = 10.35 N
Multiply weight times height = PE
2007-02-01 04:56:47 · answer #3 · answered by Sam M 2 · 1⤊ 2⤋