A school sent 5 students to a spelling bee. The team was made up of 4 people How manu combinations of 4 students could make up the team???
a. 80
b. 30
c.120
d. 60
2007-02-01 04:08:10 · 8 answers · asked by cervante02 1 in Science & Mathematics ➔ Mathematics
5C4=5!/(5-4)!=c
2007-02-01 04:14:22 · answer #1 · answered by Maths Rocks 4 · 1⤊ 0⤋
The answer is C:
5*4*3*2=120
2007-02-01 04:52:49 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Hmm... It seems to me that if the "order" on the team doesn't matter, there are only 5 combinations of the group of four (basically who is left out.) If on the other hand (as judging by the multiple choice answers) order does matter, we can do it this way.
We have 5 choices for team member 1.
We choose from the 4 remaining for team member 2.
We choose from the 3 remaining for team member 3.
We choose from the 2 remaining for team member 4.
Therefore, we have 5*4*3*2 choices, or 120 combinations.
2007-02-01 04:19:59 · answer #3 · answered by deken_99 2 · 2⤊ 0⤋
5*4*3*2 = 120
2007-02-01 04:12:42 · answer #4 · answered by Riyah 3 · 1⤊ 0⤋
C:~(5)(4)(3)(2) = 120
2007-02-01 04:19:07 · answer #5 · answered by SJama 2 · 1⤊ 0⤋
C
The first person on the team could be any of (5) people
The second person could be any of the remaining (4) people
The third person could be any of the remaining (3) people
The fourth person could be either of the remaining (2) people.
(5)(4)(3)(2) = 120
2007-02-01 04:11:38 · answer #6 · answered by MamaMia © 7 · 1⤊ 0⤋
uhh dude its 120 ...basic math? haaa! 5*4*3*2*1
2007-02-01 04:16:25 · answer #7 · answered by McKenzie 2 · 1⤊ 2⤋
nPr(5,4) = 120 combinations
2007-02-01 04:21:36 · answer #8 · answered by ryanric2000 1 · 1⤊ 1⤋