parallel to the road. if the train's speed is 75 km/h , how long does it take the car to pass it. What is the result if the car and train are travelling in opposite directions?
2007-02-01 03:58:10 · 5 answers · asked by alanis118 1 in Science & Mathematics ➔ Physics
The car is going 20 km/h faster than the train, (95-75=20) so it will take
(1.10 km)/(20 km/h) =0.055 hours (or 3.3 minutes or 3 minutes and 18 seconds)
In the opposite direction you add the speeds:
95 +75=170 km/h
(1.10 km)/(170 km/h) = .00647 hours (or 0.388 minutes, or 23.3 seconds)
2007-02-01 04:06:40 · answer #1 · answered by borscht 6 · 9⤊ 0⤋
Car length is ignored
95 km/h = 95000/(60x60) m/s = 475/18 m/s
75 km/h = 75000/(60x60) m/s = 375/18 m/s
Extra length travelled by the car in 1 second
= 475/18 m/s - 375/18 m/s
= 100/18 m
Extra distance to travel
= 1.1 km
= 1100 m
Time required
= 1100 /(100/18) s
= 1100 x 18 / 100
= 198 seconds
Second part
Distance travelled in 1 second
= 475/18 + 375/18
= 950/18
Time required
= 1100 /(950/18) s
= 1100 x 18 / 950 s
= Use your calculator
2007-02-01 04:15:47 · answer #2 · answered by Sheen 4 · 1⤊ 2⤋
Same direction, the resultant velocity is the difference:
(95-75)*t=1.1
In the opposite direction, it is the sum:
(95+75)*t=1.1
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2007-02-01 04:07:48 · answer #3 · answered by odu83 7 · 2⤊ 1⤋
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2016-05-24 01:59:57 · answer #4 · answered by Jennifer 4 · 0⤊ 0⤋
resultant velocity=95km/h-75km/h=20km/h->0.5555...m/s
1.1km=1100m
t=displacement/velocity,1100/0.5555=1980s=33mins
when opposite direction
resultant velocity=95+75=170km/h=47.2m/s
1100m/47.2m/s=23.3s
2007-02-01 04:39:49 · answer #5 · answered by Anonymous · 1⤊ 0⤋