Equipotential sufaces and electric field?

Question

Suppose a uniform electric field of magnitude 115.0 N/C exists in a region of space. How far apart are a pair of equipotential surfaces whose potentials differ by 2.0 V?

I know 115.0 N/C is the same as 115.0 V/m and it seems i should just divide it by 2.0 V 2 / 115 = .017 m but this isn't correct

Any suggestions??

Answer 1

Who told you that 0.17 m is incorrect? If the field is uniform and the gradient is 115 V/m the ratio
115 V/1 m ≡ 1.0 V/ 0.0085 m holds throughout the field. In other words, if dV/ds = k then V = ks + C.