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I need to figure out what is the Final Velocity (Vf) of a rockect when the motor stops at 16 secs (T1). I know the Accelrations was 27.0. So here are my values. V0 = 0 T0 = 0 Y0 = 0 T1 = 16 Secs A = 27.0

I am right by useing the Accelrations formula to get the Final Velocity?

A = Vf - Vi / Tf - Ti I get 27.0 = Vf/16 27 * 16 = 432 Velocity. Is this correct?

2007-02-01 01:19:56 · 3 answers · asked by antihero1776 1 in Science & Mathematics Physics

3 answers

Vf = at = 27 * 16 = 432

2007-02-01 01:26:16 · answer #1 · answered by gebobs 6 · 1 0

v=at=27 x 16=
v=432 something /seconds
Thumbs up!

2007-02-01 09:24:48 · answer #2 · answered by Edward 7 · 1 0

Yes it is correct

2007-02-01 09:22:54 · answer #3 · answered by catarthur 6 · 1 0

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