A rocket has a mass of 100 kg. The force produced by the engine of the rocket is 3000 N in the direction against the force of gravity. What is the acceleration of the rocket?
A. 10 m/s²
B. 20 m/s²
C. 30 m/s²
D. 40 m/s²
2007-02-01 00:59:04 · 7 answers · asked by Jason 1 in Science & Mathematics ➔ Physics
The answer is anywhere between 20 amd 30 m/s^2. What the problem doesn't state is how high is the rocket compared to earth.
If it is resting on the ground then g can be estimated at 10m/s^2 but what if the rocket is a million km from earth? Then g will be negligible but still in the direction of earth.
2007-02-01 01:28:39 · answer #1 · answered by catarthur 6 · 0⤊ 0⤋
a = F/m = 3000/100 = 30
Less g = 10 gives 20
2007-02-01 01:04:30 · answer #2 · answered by gebobs 6 · 1⤊ 0⤋
we can have the free body diagram of the object.
in afree body diagram we have all the forces acting on a
system.
in the given problem the forces acting on the rocket at that instant are IT S WEIGHT DOWNWARD THE THRUST PROVIDED BY THE ENGINE UPWARDS .according to newtons second law of motion the net force acting onthe body is equal to
the product of mass and accelaration..
3000-100g=100 x a
rake g=10m/s^2
3000-1000=2000=100 x a
a=20m/s^2
2007-02-01 01:32:23 · answer #3 · answered by dheeru 2 · 0⤊ 0⤋
(3000/100) - 10 = 20.
ans : B
2007-02-01 02:36:31 · answer #4 · answered by Pearlsawme 7 · 0⤊ 0⤋
Force = mass * Acceleration
3000N = 100kg * A
3000N / 100kg = A
A = 30m/s^2
2007-02-01 01:04:05 · answer #5 · answered by The_Amish 5 · 0⤊ 0⤋
according to the 2nd newtons law
Σf=ma (1)
Σf=F-W=F-mg=3000N-100Kg*10m/s²=3000N-1000N=2000N
(1)=>2000N=100kg*a=>
a=20m/s²
so the right answer is B!
2007-02-01 02:29:25 · answer #6 · answered by Anonymous · 0⤊ 0⤋
20m/s²
2007-02-01 01:16:35 · answer #7 · answered by k.sravan 1 · 0⤊ 1⤋