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An object weighs 12 N on earth. When it is brought to Mars, it has a weight of 4.8 N. What is the acceleration due to gravity on Mars? (Taking the acceleration due to gravity on earth is 10 m/s²)

A. 4.0 m/s²
B. 4.8 m/s²
C. 10 m/s²
D. 12 m/s²

2007-02-01 00:57:53 · 8 answers · asked by Jason 1 in Science & Mathematics Physics

8 answers

A...procedure is...first take out mass from the earth factors then use it in mars...F=ma

2007-02-01 01:04:21 · answer #1 · answered by catty 4 · 0 0

Since the mass does not change, you can just equate the two equations:

F/g (Mars) = F/g (Earth), ergo

g(mars) = F(mars)/F(earth) * g(Earth) = 4.8/12 * 10 = 4

2007-02-01 01:07:15 · answer #2 · answered by gebobs 6 · 0 0

mass of an object is same every where in the universe.
weight of the object varies from place to pla ce according to the gravity over that place.
weight =mass x gravity
in the given problem weight on earthis=12 N
so mass=weight/gravity
mass=12/10 =1.2kg
gravity(mars)=weight(mars)/mass
=4.8/1.2 =4m/s^2

2007-02-01 01:13:40 · answer #3 · answered by dheeru 2 · 0 0

Wt. on earth=12N
This implies mass*10=12
Thus mass=1.2

on mars, mass *(acceleration due to gravity on mars)=4.8
This implies (1.2)*(acceleration due to gravity on mars)=4.8
Therefore acceleration due to gravity on mars=4.8/1.2 = 4

2007-02-01 01:18:17 · answer #4 · answered by Malini 1 · 0 0

You kinda responded your person question. that is experiential and relative to the guy. The longer we live, the extra actual we start to appreciate longer and longer instruments of time by using fact we've experienced them. as a result, the 'shorter' instruments of time advance into something that 'look' to bypass extra rapidly as our wakeful concentration turns into extra attuned to longer intervals. Doug

2016-12-16 18:33:28 · answer #5 · answered by Anonymous · 0 0

(4.8)* 10/ 12= 4m/s2

2007-02-01 02:26:55 · answer #6 · answered by mitu 2 · 0 0

a = 4.8 / (12 /10) = 4

Ans :A.

2007-02-01 02:39:58 · answer #7 · answered by Pearlsawme 7 · 0 0

4m/s²

2007-02-01 01:17:41 · answer #8 · answered by k.sravan 1 · 0 0

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