A truck is going 80 miles an hour. From behind, a car is trying to catch up to the truck. How fast does the car have to travel to catch up with the truck?
2007-02-01 00:55:13 · 5 answers · asked by SARA P 2 in Science & Mathematics ➔ Mathematics
Within 1 and 1/2 miles?
2007-02-01 00:56:51 · update #1
Insufficient information. How far behind is the car?
2007-02-01 00:58:24 · answer #1 · answered by gebobs 6 · 0⤊ 0⤋
a) Judging via utilising the equation given, it may look that the particle is being speeded up at a consistent cost. consequently, its preliminary speed is the cost of the middle term -9t (its cost is -9). Its preliminary speed is consequently -9 cm/s b) the 1st term (t^2) is a million/2 the acceleration ingredient; it has a value of +a million. v(t) = 2a*t + v(0) 0 = 2*t + (-9) t = 4.5 consequently after 4.5 seconds, the particle might have a speed of 0 cm/s c) At t =0, the particle is at place 8. At t = 4, the particle is at 4*4 - 9*4 + 8 = -12. It consequently has a displacement of -20 cm. it fairly is accepted speed is consequently ... -20 cm/ 4 seconds = -5 cm/s consequently its accepted speed is -5 cm/s d) the person-friendly speed 4 the 1st 4 seconds is 5 cm/s (no sign as that exhibits direction). additionally be huge conscious that the direction of the particle did now no longer exchange. If it had replaced, then the person-friendly speed does now no longer have been actual the cost of the person-friendly speed.
2016-11-02 01:10:49 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Faster than 80 miles per hour.
2007-02-01 01:01:34 · answer #3 · answered by catarthur 6 · 0⤊ 0⤋
Like the guy above said insufficient info.....theres not enough info to work out the solution for it.....
2007-02-01 01:00:03 · answer #4 · answered by §hãðôw™ 4 · 0⤊ 0⤋
81 mph
2007-02-01 01:07:06 · answer #5 · answered by n5vhf_gene 2 · 0⤊ 0⤋