An object moves uniformly around a circular path of radius 21.5 cm, making one complete revolution every 2.20?

Question

An object moves uniformly around a circular path of radius 21.5 cm, making one complete revolution every 2.20 s.
(a) What is the translational speed of the object
(b) What is the frequency of motion in hertz?
(c) What is the angular speed of the object?

Answer 1

use
a) v=w*r
w= 2pie /2.20

b) f = 1/t
t = 2pie/w

c) w = 2pie/t

Answer 2

314

Answer 3

Let:

Radius = r, period = T, frequency = f, translational or tangential speed = v and angular freq (or speed) = w.

We know that:

Frequency f=1/T
Angular frequency (or speed) w=(2*pi)*f
Period T=(2*pi)/w
Translation speed v=rw

So we can calculate that:

Translational speed v=rw = 0.215 * ((2*pi)/2.20) = 0.614m/s
Frequency f = w/(2*pi) = 1/T = 0.455Hz
Angular speed = w = (2*pi)*f = 2.86 rad/s

Hope this helps.