2007-01-31 21:34:51 · 16 answers · asked by Deepak 1 in Science & Mathematics ➔ Mathematics
http://www.albireo.ch/temperatureconverter/
2007-01-31 21:45:39 · answer #1 · answered by Anonymous · 0⤊ 0⤋
C° = (5/9)(F° - 32°)
°Fahrenheit =9/5 (°Centigrade) + 32
Remember 212 °Fahrenheit =100 °Centigrade
Remember 32 °Fahrenheit =0 °Centigrade
(let us proove,
212=9/5(°Centigrade)+32
(212-32)*5/9=°Centigrade
180*5/9=°Centigrade
900/9=°Centigrade
100=°Centigrade)
2007-02-01 02:37:26 · answer #2 · answered by Anonymous · 2⤊ 0⤋
Basic linear algebra can help you develop the formula. You denote the two known points of C and F, as (C, F): boiling point of water (100, 212) and freezing point of water (0, 32). Use those two points and the point-slope formula to calculate.
Slope: (212 - 32)/(100 - 0) = 180/100 = 9/5
F - 32 = (9/5)(C - 0)
F - 32 = (9/5) C
F = (9/5) C + 32
2007-01-31 21:45:53 · answer #3 · answered by Mathematica 7 · 0⤊ 0⤋
F= ( 9 / 5) C + 32
2007-02-02 19:59:26 · answer #4 · answered by nirupa 2 · 0⤊ 0⤋
°Fahrenheit =9/5 (°Centigrade) + 32
2007-01-31 21:40:56 · answer #5 · answered by Pradeep Chelani 2 · 0⤊ 0⤋
F° = (9/5)C° + 32°
C° = (5/9)(F° - 32°)
2007-01-31 21:40:41 · answer #6 · answered by Northstar 7 · 0⤊ 0⤋
I think it is F° = (9/5)C° + 32°.
See you.
2007-01-31 22:23:21 · answer #7 · answered by Anonymous · 0⤊ 0⤋
C/5=F-32/9. this relation is for both celcius to farenheit and vice versa.
2007-01-31 21:42:27 · answer #8 · answered by addiz 1 · 0⤊ 0⤋
F=32+9/5C.So using equations u can find it
2007-02-01 00:20:21 · answer #9 · answered by Nisarg S 1 · 0⤊ 0⤋
f*=9/5(c*)+32
2007-02-02 06:52:41 · answer #10 · answered by Anonymous · 0⤊ 0⤋
°F = (5/9)(c - 32) °C = (4/9)(c - 32)
2007-01-31 21:45:29 · answer #11 · answered by DKD 2 · 0⤊ 0⤋