integrate log(sinx) with the limit (0 to Pi/2)?

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integrate log(sinx) with the limit (0 to Pi/2)?

2007-01-31 21:30:23 · 2 answers · asked by Arun R 1 in Science & Mathematics ➔ Mathematics

2 answers

Ok so you have to realize that you would get the same integral
if sinx was replaced by cos x or sin 2x. Use the formula sin 2x = 2 sinx cos x and you will get an equation for your integral. In the end you should get -pi log 2 / 2.

2007-01-31 21:48:11 · answer #1 · answered by gianlino 7 · 1⤊ 0⤋

let f be the integral sign

f log(sin(x)), 0 =(log(sin(x))-log(e))x

2007-02-01 05:43:26 · answer #2 · answered by josiahitsgoodtohavesomeself-ctrl 2 · 0⤊ 2⤋