What is the domain of f(x) = ln(ln(ln(x-1)))? quick thanks =]?

Answer 1

x=6.7

Answer 2

As negative numbers don´t have log,starting fromleft to right

ln(ln(x-1)>0 ==> ln(x-1)>1 ==> x-1> e and x> e+1

Answer 3

x > e + 1
The value of ln is undefined at 0 or below, so ln(ln(x-1)) > 0
The value of ln(1) is zero, and ln is a strictly increasing function, so
ln(x-1) > 1
and ln(e) = 1, so
x-1 > e
or x > e + 1, about 3.718281828.

Answer 4

y = f(x) = ln(ln(ln(x - 1)))

The domain is
x - 1 > e
x > e + 1

Answer 5

f(x)=ln(ln(ln(x-1)))

because ln(ln(ln(x-1)))
ln(ln(x-1))>0
ln(x-1)>e^0
ln(x-1)>1
x-1>e^1
x-1>e
x>e+1

so ,domain is {x|x>e+1,x:R}