Question: a charge of q = +7.50 uC is located in an electrical field. The x and y components of the electric field are E(x) = 6.00 x 10^3 N/C and E(y) = 8.00 x 10^3 N/C, respectively. (a) What is the magnitude of the force on the charge? (b) Determine the angle that the force makes with the +x axis.
My Approach:
I have the answers to this problem; however, part (b) is where i am not getting the answer. I have theta = 53.13 degrees...my teacher marked it wrong for equalling 53 degrees. so what are his intentions? i asked him, but i cant understand his mumbling lol. anyways, i ask you people!
2007-01-31 18:13:40 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The force is q*E, so you can get x and y force components. The force magnitude is √[Fx^2 + Fy^2], and the angle is arctan[Fy/Fx]. The results are F = 7.5*10^-5N and theta = 53.13º I don't understand why this is wrong. Go back and ask for a good explanation, and don't give up until you understand it. Perhaps the teacher wanted the answer in radians (= 0.927).
2007-01-31 18:27:41 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
tan Ó¨ = 8/6
Ó¨ = 53.13 degree.
Regarding the intentions of your teacher, he is the person to answer.
2007-02-01 03:04:36 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
You are right, screw him.
2007-02-01 02:47:55 · answer #3 · answered by Iman S 2 · 0⤊ 0⤋