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I need help with this 5 part question that I have no idea how to solve.

Factors and Remainders
-------------------------------------
1. When x^3 + a is divided by x + 2, the remainder is known to be -15. Find the numerical value of "a".

2. Find the value of "a" above when x + 2 is replaced by x - 2.

3. Find the smallest value of "a" for which x^3 + a is exactly divisible by x+2

4. If x - a is a factor of x^2 + 2ax - 3, find the numerical value(s) of "a".

5. Find the remainder when x^6 + 1 is divided by x - m.
----------------------------------------------

Please help me, with explanations of how to do each step. Math has always been my weakest subject, and if possible, can anyone at least point me in the direction, and I'll do the calculating?

Thanks a lot,

Matt

2007-01-31 18:13:21 · 3 answers · asked by Matt B 1 in Science & Mathematics Mathematics

Also, I need help ASAP so I can turn this in a few hours. I'll greatly appreciate anyone's help.

2007-01-31 18:14:50 · update #1

I cannot ask the teacher because its a project.

2007-01-31 18:25:18 · update #2

Please help.... :\

2007-01-31 19:07:54 · update #3

3 answers

start to divide! thats the hint, if you don't know why get a text book, but here are the answers for now:

1.
(x^3+a) | x+2
-------------------
-x^3-x^2 x^2-2x+4
-----------
-2x^2+a
2x^2+4x
-----------
4x+a
-4x-8
------------
-8+a (the remainder) = -15 ---> a=-7

2. the same procedure

3. set remainder=0 --> a=8

4. devide mate it gotta be a=-1 or a=1

5. ran outa patience

2007-01-31 18:29:58 · answer #1 · answered by Iman S 2 · 0 0

1.
. . . . x^2 - 2x + 4
x + 2)x^3 + . . . . . . . . . + a
. . . . x^3 + 2x^2
. . . . . . .. - 2x^2
. . . . . . .. - 2x^2 - 4x
. . . . . . . . . . . . .. 4x
. . . . . . . . . . . . . 4x + 8
. . . . . . . . . . . . . . . . - 8 + a = - 15

All the rest use the same approach. #2 and #3 can be solved by inference from #1.

2007-02-01 03:13:48 · answer #2 · answered by Helmut 7 · 0 0

please ask ur maths teacher

2007-02-01 02:20:37 · answer #3 · answered by How are u? 3 · 0 0

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