does anyone have any idea how to solve y=9-x^2, y=x^2 X=0?

Question

im supposed to use the shell method to find the volume of the enclose solid

Answer 1

I agree with the guy above, you need horizontal shell for this one.

edit,

sorry, vertical shell, you will revolve it around x=0.

Think of it as an infinite number of consecutive cylindrical shells and with walls infinitely thin and upper and lower edges defined by the 2 eq'ns.

Answer 2

hi I am not sure if the eqn. is correct is that X=0 or multiple sign or what if its y=9-x^2,y=x^2 then
y=4.5 & x=2.12
bt X=0 then y=0 also &that 9-x^2=0
(3-x)(3+x)=0
X=-3 or 3 ¬ 0...hope i helped

Answer 3

y=x^2 is a parabola, opening facing up, with its minimum at the origin (0,0)

y=9-x^2 is a parabola, with its opening facing down, and its maximum at (0,9)

You would have to rotate the 2 parabolas to create a solid. Are you at all familiar with the shell method? A brief discussion of it can be found here:

http://library.thinkquest.org/3616/Calc/S3/TSM.html

Answer 4

sadly no :( I just want 2 points..