I am having trouble with this problem.....
Y= X^2 + X -6
I need help finding the X intercept !! Thank you
2007-01-31 16:15:37 · 5 answers · asked by CookFrNW 3 in Science & Mathematics ➔ Mathematics
The x-intercept is where y = 0; so put that in your eqn:
x^2 + x - 6 = 0
(x+3)(x-2) = 0 so that the x values for y inter = -3,2
2007-01-31 16:25:24 · answer #1 · answered by kellenraid 6 · 0⤊ 0⤋
To find the X intercept substitute y=0 and solve for x.
That gives x= -3 and 2
2007-02-01 00:21:43 · answer #2 · answered by Mohammed S 2 · 0⤊ 0⤋
y=(x+3)(x-2)
x intercept: y=0
0=(x+3)(x-2)
x=-3 and x=2
2007-02-01 00:22:32 · answer #3 · answered by rh4p50dy 1 · 0⤊ 0⤋
If you have a graphing calculator:
push the y= button and plug that in
then do 2nd trace (which is calc) and select zero
then do right bound and left bound to find the exact intercepts
2007-02-01 01:22:41 · answer #4 · answered by Anonymous · 0⤊ 0⤋
you need to begin by factoring
y = (x+3)(x-2)
set both equal to zero
x = -3 AND 2
2007-02-01 00:29:48 · answer #5 · answered by imagonner_2007 1 · 0⤊ 0⤋