trig question again?

Question

i need to derive sin = tan from sin^2 + cos^2 =1 using trig identities

write sin in terms of tan using sin^2 + cos^2 =1

Answer 1

because 1 + tan²x = sec²x

and sec²x = 1/cos²x

you can say that 1 + tan²x = 1/cos²x

multiply by cos²x:

cos²x + cos²xtan²x = 1

because sin²x + cos²x = 1
sin²x = 1 - cos²x

therefore, sin²x = cos²xtan²x
and sinx = cosx tanx

Answer 2

i need to derive sin = tan from sin^2 + cos^2 =1 using trig identities.
Sorry, can't be done because it isn't true.

Answer 3

a million) ingredient out sin^a million/2 from unique equation sin^a million/2(cos x - sin^(4/2)xcosx 2)sin^(4/2)x = sin^2 x by way of simplificaiton 3) sin^2 x = a million - cos^2 x by way of pythagorean identities 4) rewrite... and simplify... it's going to all artwork out using fact the superb area

Answer 4

(tan(x) )^2 = (sin(x))^2/[1-(sin(x))^2)]
1/(tan(x) )^2
= [1-(sin(x))^2)]/(sin(x))^2
= 1/(sin(x))^2 -1

Solve for sin(x),
sin(x) = ± tan(x)/[1+(tan(x) )^2 ]^(1/2)