College Algebra Problem?

Question

okay i have a formula...
P=1-R-D/R

I need to switch this problem around to solve for R
and then switch it around to solve for D.

I am having trouble not very good at Math :D thanks

Answer 1

R^2=1 - P - D

D= 1 - P - R^2

Answer 2

Is it P = 1 - R - D/R or is it P = (1 - R - D)/R?

In the 1st case, multiply by R:

RP = R - R² - D
R² + RP - R + D = 0
R² + (P-1)R + D = 0

then use the quadratic formula with a = 1, b = P-1, and c = D.

More likely you should have used parentheses, so in the second case, multiply by R and get

RP = 1 - R + D
RP + R = 1 + D
R(P+1) = 1 + D
R = (1+D) / (P+1)

Answer 3

(80 5 + 80 3 + ninety + ninety 4 +88 + 80 4 + x) / 7 = 86 the position x equals the seventh try score that we opt to discover. (524 + x)/7 = 86 524 + x = 86 *7 x = (86 * 7) - 524 x = seventy 8 so he desires a seventy 8 on his seventh exam to get an frequent of 86.

Answer 4

P=1-R-D/R

1.We want to make sure we only have things with R in them on one side.

P-1 = -R-D/R

2. Factor out R

P-1 = -R(1+D/1) or P-1 = -R(1+D)

3. Get rid of the negative sign on the side with R

-(P-1) = R(1+D)

4. Isolate R

-(P-1)/(1+D) = R

there you go. also written as:

R = - (P-1)/(1+D)

solve for D

P=1-R-D/R

1. Make sure we only have things with D on them on one side of the equation so we subtract both sides by (1-R)

P-(1-R) = - D/R also written as

P - 1 + R = - D/R

2. Get rid of the negative sign on the side that has a D in it:

-(P - 1 + R) = D/R

3. Isolate D by multiplying both sides by R

-R( P - 1 + R) = D

there you go. Also written as

D = -R(P-1+R)

or

D = -R^2 - RP + R

but it looks cleaner if you factor out the R

Answer 5

Multiply through by R

PR=R-R^2-D (**)
R^2+PR-R+D=0
R^2+R(P-1)+D=0

To solve for R, use the quadratic formula.

From (**) we see that D=R-R^2-PR

Of course if you meant P=(1-R-D)/R then multiply both sides by R to get PR=1-R-D.

D=1-R-PR

To solve for R, move the R to the left side:
PR+R=1-D
R(P+1)=1-D
R=(1-D)/(P+1)

Answer 6

P=1-R-D/R multiply both sides by r
pr=r-r^2-d subtract pr from each side from each side
-r^2+r-pr-d=0 multiply by -1
r^2+(p-1)r+d=0

r=((1-p)+/-√((p-1)^2-4d))/2

pr=r-r^2-d subtract r-r^2 from each side
r^2+(p-1)r=-d
d=-r^2+(1-p)r

Answer 7

Ist Value: R=(1/2)*[-(P-1)+((P-1)^2 - 4D)^1/2]
2nd Value: R=(1/2)*[-(P-1)-((P-1)^2 - 4D)^1/2]

D=R(1-R-P)

Answer 8

P(R)= R(1-R) - D
-D= P(R) - R(1-R)
D= -P(R) +R(1-R)

P+1= R-D/R
P+1+D/R = R

Answer 9

some of the answers above doesn't seem right.

I agree with ambushe's answers, though.