please help me solve for x:
159^(x) = 2.099
2007-01-31 15:38:22 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
SORRY thats
1.59^(x) = 2.099
2007-01-31 15:39:35 · update #1
you havta use logs
1.59^(x) = 2.099
so, in order to find the value for x, take the log of both sides
log 1.59^x = log 2.099
using the power law, bring the exponent to the front of the log
x log 1.59 = log 2.099
isolate for x
x = log 2.099/log 1.59
x = 1.60
2007-01-31 15:43:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Taking log of both sides
x*log1.59 = log 2.099 so x= log 2.099 /(log 1.59) = 1.5989
2007-02-01 06:53:58 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
159^x = 2.099
log 159^x = log 2.099
x log 159 = log 2.099
x = (log 2.099) / (log 159)
2007-01-31 23:46:34 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
lg(1.59^x) = lg2.099
xlg1.59 = lg2.099
x = (lg2.099)/(lg1.59)
= 0.160 (3 s.f.)
2007-01-31 23:45:38 · answer #4 · answered by rfedrocks 3 · 0⤊ 0⤋