Cost, C=12.30x + 98000
Revenue, R = 17.98x
A profit when
R > C
17.98x > 12.30x + 98000
5.68x > 98000
x > 17253.521
2007-01-31 15:42:32
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answer #1
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answered by seah 7
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The equations must be referring to marginal cost, and marginal revenue, which are defined as the slope of the total revenue and total cost curves.
Anti - differentiate both curves to get
a) Total cost
integral of 12.30x + 98,000 = 6.15x^2 + 98,000x
b) total revenue
integral of 17.98x = 8.99x^2.
Then subtract the total revenue by the total cost curve to get total profit.
= (8.99x^2) - (6,15x^2 + 98,000x)
= 2.84x^2 - 98,000x
Graph this function on your calculator, and give the domain for which x yields a positive value.
Or solve explicitly.
2.84x^2 - 98,000x > 0
x(2.84x - 98,000)>0
so 2.84x > 98,000
x> 34507
2007-01-31 15:47:03
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answer #2
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answered by elkabong2500 2
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the cost =revenue equation, then profit begins where the two lines intersect, solving
so set the 2 equal
17.98x=12.30x +98,000
Then5.68x=98,000
And x=17,253.52
Rounded 17,254 I assume it would be $
2007-01-31 15:50:12
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answer #3
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answered by James M 6
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If c=r, then 17.98x = 12.30x +98000
17.98x - 12.30x = 98000
5.68x = 98000
x = 17253.5211
Therefore for making a profit x should be greater than 17253.5211
2007-01-31 15:49:47
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answer #4
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answered by cvasan 2
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2016-11-02 00:37:08
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answer #5
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answered by ? 4
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solve 12.30x + 98000 = 17.98x
x=98000/(17.98-12.30)=...
all x's above the solution will have positive profit, so you answer is x>...
2007-01-31 15:42:25
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answer #6
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answered by Anonymous
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17.98x>12.30x+98,000
5.68x>98,000
x>17.254
2007-01-31 15:43:24
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answer #7
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answered by emerzagor 2
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