help me with this expression please?

0 ⤊

(e^[2x-8]) / (e^[2x-5])

THANKS!

2007-01-31 15:27:44 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

(e^[2x-8]) / (e^[2x-5])
= e^[2x-8 - 2x+5]
=e^[-3] = 1/e^3

2007-01-31 15:31:59 · answer #1 · answered by Anonymous · 0⤊ 0⤋

As you are dividing powers with the same base you must substract exponents.
Expression = e^(2x-8-2x+5)= e^(-3)

2007-02-01 07:25:30 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋

Remember that when two exponents are dividing each other, the exponents are subtracted:

So

e^(2x-8) / e^(2x-5) = e^[(2x-8 - (2x-5)] = e^-3

2007-01-31 23:32:10 · answer #3 · answered by AibohphobiA 4 · 0⤊ 0⤋