Find all real solutions using radians
sin2x= .35
I know how to do the problem but the answers are infinite please answer my life depends on it
2007-01-31 15:05:57 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Taking the inverse sin of both sides, you get
2x = sin^(-1)(0.35)
x = (1/2)sin^(-1) (0.35)
Notice though that the sine wave y=sin(2x) has a period of 2pi/2 = pi. So it repeats itself every pi units. So if x is shifted over in any increment of pi, you'll get the same answer. So your full answer is n*pi + (1/2)sin^(-1) (0.35) for n=0,1,2,3...
2007-01-31 15:18:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1) The equation has two solutions in the closed interval [0, pi]; call them x1, x2.
2) then, x1 + n * pi; and, x2 + n * pi; for all positive and negative integers, are also solutions
2007-02-01 00:22:11 · answer #2 · answered by 1988_Escort 3 · 0⤊ 0⤋
your answer will not be a number. it will be another equation you have to add the value of the period that (sin2x) has and multiply that by x i believe that comes out to be .35 +(pi)x
2007-01-31 23:12:21 · answer #3 · answered by munkeyman111 1 · 0⤊ 0⤋
HM. if sin(2x)= 0.35
then 2x = arcsin (0.35) and
x = arcsin (0.35) / 2
which calculates to 0.178786 radians.
2007-01-31 23:19:48 · answer #4 · answered by ZORCH 6 · 0⤊ 0⤋