Ayuda por favor.... 5a squared + 34a +2 = 9?

Question

factoring

Answer 1

5a^2+34a+2=9 Rearrainge
5a^2+34a-7=0

5*7 = 35, therefore actors of 35 which subtract to 34 would be 35 and -1

5a^2+35a-a-7=0
Separate first two terms and last two terms
(5a^2+35a)+(-a-7)=0

Factor what you can, including the negative out of the second set.

5a(a+7)-1(a+7)=0

and then continue by factoring the (a+7) ...

(a+7)(5a-1)=0

Answer 2

Rewrite as 5a² + 34a - 7 = 0, then look for factors of 5•7 that subtract (because of the minus in front of 7) to make 34. Clearly that's 35 and 1. So

5a² + 34a - 7 = 0
(5a - 1)(a + 7) = 0

5a - 1 = 0
5a = 1
a = 1/5

or

a + 7 = 0
a = -7

Answer 3

First answer not complete.

5a^2 + 34a - 7 = 0
Since 5*(-7) = -35, look for two numbers with opposite signs whose total is +34.
Obviously they are +35 and -1, so write the quadratic as

5a^2 + 35a - a - 7 = 0
5a(a+7) -1(a+7) = 0

Now (a+7) is a common factor on the left side:

(a+7)(5a - 1) = 0
Hence
a+7 = 0 or 5a - 1 = 0
Therefore
a = -7 or +1/5

Answer 4

(a+7)(5a-1)