4 ( c + 3 ) - ( c - 1 ) = 64?
4c + 12- c +1 = 64
3c +13 = 64
3c= 64-13
3c= 51
c= 17
2007-01-31 14:40:58
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answer #1
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answered by ann 1
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4c + 12 -c +1 = 64
3c + 13 = 64
3c = 64 - 13
3c = 51
c = 17
To check:
4 (17 + 3) - (17 - 1) = 64
4 (20) - 16 = 64
80 - 16 = 64
64 = 64
2007-01-31 22:37:12
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answer #2
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answered by Marv 2
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c= 17
2007-01-31 22:34:06
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answer #3
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answered by stud muffin 2
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4c+12-c+1=64
3c+13=64
3c=64-13
3c=51
c=51/3
c=17
2007-01-31 22:39:02
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answer #4
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answered by deus82 3
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4(c+3)-(c-1)=64
4c+12-c+1=64
3c=64-13
3c=51
c=17
2007-01-31 22:35:26
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answer #5
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answered by Michelle M 2
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4(c+3)-(c-1)=64
4c+12-c+1=64
3c+13=64
3c=51
c=17
2007-01-31 22:48:50
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answer #6
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answered by πρ 6
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3c=51
c = 17
2007-01-31 22:33:35
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answer #7
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answered by Anonymous
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4c+12-c+1=64
5c+13=64
5c=51
c=51/5
2007-01-31 22:35:27
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answer #8
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answered by Mikey 2
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You poor thing. School will be over in a few years and you will not have to think about those things. Since I do not have to think of those things, I don't.
2007-01-31 22:37:02
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answer #9
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answered by grannywinkie 6
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3c=56
c=56/3, then simplify
2007-01-31 22:35:59
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answer #10
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answered by psychoffspring 2
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