solve for h?

Question

I need to solve for h
55= h[ (h+1)/2]
please show work
thanks

Answer 1

55=h[(h+1)/2]
110=h(h+1)
0=h^2+h-110
0=(h+11) (h-10)

equivalent to
h=-11 and h=10

Answer 2

First, realize you have a binomial....

55= h[ (h+1)/2] .. original formula
55/h = (h+1)/2 .. divide both sides by h
55(2) = h(h+1) .. cross multiply
110 = h^2 + h .. simplify
h^2 + h - 110 = 0 .. re-arrange to =0 format
(h-10)(h+11) = 0 .. factor
h=10, or h=-11 .. solve each zeros

Answer 3

the answer is 10

Answer 4

55=h[h+1)/2]
55= h(to the second power) +1 / 2
55= h (to the second power) + 0.5
-0.5 -0.5
.........54.5=h.......

there you go sweetie !