I do believe in black holes. One of the ways they are formed is when a star collapses onto itself and so all its weight is compressed into the size of the tip of a needle. All this weight then "drags" the fabric of time and space down. the force is so strong that not even light can escape. Once a black hole has taken in all it is able to take, it ruptures and so a sister white hole is formed. All that energy is then released into a "new" universe. The only thing of quantum physics i know of is that a neuron particle from an atom "disappears" from the atom it is in for like a nanosec. where does it go? it is believed to go to other universes. there are eleven universes believed to exist.
2007-01-31 15:08:42
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answer #1
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answered by Ham 2
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We have observational evidence for black holes. They're no longer theoretical.
The major relationship between a black hole and quantum mechanics is in the singularity of a black hole, quantum mechanics is the only science that has predictive power.
Additionally, it's been put forth by theoretical physicists, such as Stephen Hawking, that over time, a black hole decays, losing its mass, until it ultimately disappears. This is due to the particles contained being able to quantum tunnel just beyond the event horizon and escape.
2007-01-31 16:19:25
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answer #2
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answered by Tangent . 2
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Yes, I do believe in Black Holes, because we now have their observational evidence.
A black hole spacetime seems to behave like a thermodynamic system. How could this be true? This is spacetime geometry, after all, not a cylinder of gas or a pot of liquid. The importance of this apparent thermodynamic behavior of black holes was made undeniable when black hole radiation was discovered by Hawking.
Black hole radiation, known as Hawking radiation, comes about because relativistic quantum field theory is invariant under Lorentz transformations, but not under general coordinate transformations. In flat spacetime, two observers moving at a constant velocity relative to one another will agree on what constitutes a vacuum state, but if one observer is accelerating relative to the other, then the vacuum states defined by the two observers will differ. This idea, when extended to the spacetime of a black hole, leads to the conclusion that to an observer who stays at a fixed distance from a black hole event horizon, the black hole appears to radiate particles with a thermal spectrum with temperature (in units with GN=c=1) T=1/8pMkB, where kB is Boltzmann's constant and M is the black hole mass.
Since plane waves and Fourier transforms are at the heart of relativistic quantum field theory, this effect can be illustrated using a classical plane wave, without even appealing to quantum operators.
Hawking's black hole result if the acceleration is related to the black hole mass by a=1/4M. And indeed, the acceleration at the event horizon of a black hole of mass M does satisfy a=1/4M. Why does this work so well? Because an observer held at a fixed distance from the event horizon of a black hole sees a coordinate system that is almost identical to that of an observer undergoing constant acceleration in flat spacetime.
But don't be misled by this to think that the full black hole radiation calculation is as simple. We've neglected to mention the details because they are very complicated and involve the global causal structure of a black hole spacetime.
Conservation of energy still applies to this system as a whole, so if an observer at a fixed distance sees a hot bath of particles being radiated by the black hole, then the black hole must be losing mass by an appropriate amount. Hence a black hole can decrease in area, through Hawking radiation, through quantum processes.
But if area is like entropy, and the area can decrease, doesn't that mean that the entropy of a black hole can therefore decrease, in violation of the Second Law of thermodynamics? No -- because the radiated particles also carry entropy, and the total entropy of the black hole and radiation always increases.
2007-01-31 16:49:06
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answer #3
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answered by Kristada 2
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