Parametric Equations?

Question

Eliminate the parameter to find a Cartesian
equation from these parametric equations,
x(t) = cos2(48 t) and y(t) = sin2(48 t) .
1. y(x) = 1 + x
2. y(x) = 1 + 48 x
3. y(x) = −1 + x
4. y(x) = 1 − 48 x
5. y(x) = −48 − x
6. None of the other choices is correct.
7. y(x) = −1 − x
8. y(x) = −48 + x
9. y(x) = 1 − x
10. There is no such Cartesian equation

Answer 1

#9

Remember from Trig. that cos^2 + sin^2 = 1 so sin^2=1-cos^2

since y= sin^2 (48x)= 1-cos^2 (48x)= 1-x since x=cos^2 (48x)

Answer 2

I'm assuming that you mean cos^2(48t) and sin^2(48t).

I'm not going to tell you straight out, but I'll give you a hint. What do the two expressions above equal when added together, no matter what t is?