English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1 answers

If the system has an infinite number of solutions, then both equations will represent the same line. That is, one equation will be an exact multiple of the other one.

kx + 3y = k - 3

12x + ky = k

One way to make this happen is to multiply the top equation by k and the bottom equation by (k - 3), and set the equations equal to each other.

k²x + 3ky = k² - 3k

12x(k - 3) + ky(k - 3) = k² - 3k

Now pick either the coefficient of x or y from both equations and set those equal:

k² = 12(k - 3) = 12k - 36

k² - 12k + 36 = 0

(k - 6)² = 0

k = 6

Now double-check:

6x + 3y = 3

12x + 6y = 6

The second equation is twice the first, so k = 6 is correct.

2007-01-31 15:50:47 · answer #1 · answered by Jim Burnell 6 · 0 1

fedest.com, questions and answers