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An Originally stationary car with a mass of 1500kg reaches a velocity of 15m/sec 5 sec after starting. What is the car's acceleration? How much forch was required to reach this acceleration?

2007-01-31 13:53:02 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

use vf=vi+at. a turns out to be 3 m/s^2
F=ma, F turns out to be 4500N

2007-01-31 14:34:01 · answer #1 · answered by climberguy12 7 · 0 0

Ok,

a = Δv ÷ Δt

Δv = Vf - Vi = (15m/s) - ( 0 m/s) = 15 m/s

Δt = tf-ti = 5s- 0s = 5 s

a = 15 m/s ÷ 5 s = 3 m/s^2

And for force,

F = ma

F = (1500kg) * (3 m/s^2)

F= 500 N

2007-01-31 22:19:43 · answer #2 · answered by Anonymous · 0 0

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