GCF for polynomials... help?!?!?!?
1. 24x^2+20x
2. 15x^3-18x^2-3x
3. -34x^3+102x
4. 119x^3-204x^2-17x
2007-01-31 12:58:53 · 10 answers · asked by katiekcat5 3 in Science & Mathematics ➔ Mathematics
1. 4x (6x + 5)
2. 3x (5x^2-6x-1)
3. 34x (-x^2+3)
4. 17x (7x^2-12x-1)
The GCF is the 4x, 3x, 34x, and 17x only.
I've shown the resulting factorization.
2007-01-31 13:09:04 · answer #1 · answered by Mark P 5 · 2⤊ 1⤋
Let's factor these first.
1) 4x (5x+6)
2) 3x (5x^2-6x-1)
3) -34x (x^2-3)
4) 17x (7x^2 - 12x - 1)
Looks like the GCF is just x.
However, when I look at everyone else, it seems you want the GCF of the terms in each individual one. If that is the case, then the answers are just
1) 4x
2) 3x
3) 34x (I would pull out a -34x here, to remove the negative from the x^2 term)
4) 17x
2007-01-31 13:11:28 · answer #2 · answered by dennismeng90 6 · 3⤊ 1⤋
1. 24x^2+20x=4x(6x+5) GCF=4x
2. 15x^3-18x^2-3x=3x(5x^2-6x-1) GCF=3x
3. -34x^3+102x=34x(-x^2+3) GCF=34x
4. 119x^3-204x^2-17x=17x(7x^2-12x-1) GCF=17x
2007-01-31 13:26:46 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
A-ha! You've been tricked! 2x is not the GCF of the monomials 4x^3, 6x, 2x^2, and 10. You found your problem...the x does NOT divide into the constant 10. A variable will never, ever, ever be a factor of a constant! So, what you'd do is just factor out 2, not 2x. The 2 divides all the individual monomials, and it's the highest one that does. So you'd get 2(2x^3 + 3x + x^2 + 5) One other thing: it's always nice to write the monomials in DESCENDING powers of x. So, you can change it around to 2(2x^3 + x^2 + 3x + 5). The first answer isn't wrong...it's just not as nice-looking. Of course, the question itself was a little goofy because it gave it in jumbled order.
2016-05-24 00:29:36 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Well it looks like everyone has told you the correct answer. I don't think giving you the answer will help you in the long run understand how to do these. My suggestion, if you can't figure out what they each have in common try a factor tree for the numbers. The biggest number that is shared by each tree is the greatest common factor. Then you look at the variables. The smallest they have in common is the greatest common factor. Take #4 for example. You have an x^3 an x^2 and an x^1. The smallest one is the x^1 or simply x.
2007-01-31 13:45:25 · answer #5 · answered by Carolyn D 5 · 1⤊ 0⤋
1.GCF: 4x
Simplified: 4x(6x + 5)
2. GCF: 3x
Simplified: 3x(5x^2 -- 6x -- 1)
3. GCF: -34x
Simplified: -34x(x^2 - 3)
4 GCF: 17x
Simplified: 17x(7x^2 -- 12x -- 1)
2007-01-31 13:31:17 · answer #6 · answered by rach09el 2 · 0⤊ 0⤋
ok, first, you find something that goes into the numbers. then you look at the x. x^1 is the smallest x, so that is the x that goes with the GCF of the number part
1. 24x^2 + 20x
. . . GCF of 20 and 24 is 4
. . . x^1 is the smallest x
. . .4x
. . .take 4x out of each number in the origional polynomial and write it to look like distributing.
4x(6x + 5)
. . .you can distribute to check
hope this helps so you can solve the others on your own
2007-01-31 13:22:02 · answer #7 · answered by xREDrawr 4 · 0⤊ 3⤋
Greatest common factor?
1. 2x (12x + 10)
2. 3x (5x^2 -6x -1)
3. 17x (-2x^2 +6)
4. 17x (7x^2 -12x -1)
2007-01-31 13:13:38 · answer #8 · answered by Alan 6 · 0⤊ 3⤋
1. 4x(6x+5)
2. 3x(5x^2-6x-1)
3. 17x(-2x^2+6)
4. 17x(7x^2-12x-1)
hope this helps!
2007-01-31 13:14:03 · answer #9 · answered by chris 4 · 0⤊ 3⤋
1. 4x
2. 3x
3. 34x
4. 17x
i forgot if u include the Xs :( sory but the #s are right
2007-01-31 13:11:35 · answer #10 · answered by Anonymous · 0⤊ 3⤋