2007-01-31 12:58:01 · 8 answers · asked by anonymous91 1 in Science & Mathematics ➔ Mathematics
its suppose to be (x+5)
2007-01-31 12:58:51 · update #1
y-5 = -2(x+5)^2
= -2(x+5)(x+5)
= -2(x^2+5x+5x+25)
= -2(x^2+10x+25)
= -2x^2-20x-50
y = -2x^2-20x-45
2007-01-31 13:11:35 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Ok, let's get this under control. First add 5 to both sides, so y = -2x (x =5) squared plus 5. Ignoring the fact that the equation itself gives you the answer, let's proceed, since we know that you can't get a solution for two variables out of one equation. In this case, of course, you have only one variable, but whattheheck
So you have y = 2x squared plus 20x + 5 = zero
But of course x IS 5.
So 2x squared plus 21x = zero
But that won't work as x has to be an even number.
And it can't be, since we already know it is 5.
This is a badly screwed up equation.
2007-01-31 22:27:38 · answer #2 · answered by obelix 6 · 0⤊ 0⤋
y-5=-2(x+5)^2<---(x+5)(x+5)
y-5=-2(x^2+10x+25)<---distribute the -2, and add 5 to the product
y=-2x^2-20x-45
2007-01-31 21:33:36 · answer #3 · answered by babbs 2 · 0⤊ 0⤋
y - 5 = -2(x + 5)^2
y - 5 = -2 (x^2 + 10x + 25)
y - 5 = -2x^2 - 20x - 50
y = -2x^2 - 20x -45
2007-01-31 21:31:26 · answer #4 · answered by lostlatinlover 3 · 0⤊ 0⤋
y= -2(x^2) - 20x - 45
2007-01-31 21:04:42 · answer #5 · answered by postcard_2_reno 1 · 1⤊ 0⤋
y-5=-2(x^2+10x+25)
y-5=-2x^2-20x-50
y=-2x^2-20x-45
2007-01-31 21:18:18 · answer #6 · answered by Anonymous · 0⤊ 1⤋
Hey now i know how to do my homework!!? all of you answering are such suckers..
2007-01-31 21:49:54 · answer #7 · answered by alyssa w 1 · 0⤊ 0⤋
i am assum ing this is a kid too lazy to do their own homework...buddy, the internet wont help you.
2007-01-31 21:09:47 · answer #8 · answered by The Homie Girl 2 · 1⤊ 3⤋