How much of the 60% solution was there to start and how much 0% solution was added?
2007-01-31 12:43:25 · 3 answers · asked by jill_andrews32 1 in Science & Mathematics ➔ Mathematics
This doesn't make any sense. If you have a 60% solution, then adding a 0% solution to it will only dilute it. There's no way you can water down something and come up with something stronger.
But just to go through the math anyway to show that it doesn't make any sense in the numbers either, write an equation that balances the amount of actual chemical. If x is the volume of the 60% solution, then:
0.6x + 0*25 = 0.68(25+x)
0.6x = 0.68x + 0.68*25
-0.08x = 0.68*25
So x is a negative number. You can't add "negative liters" to something.
The second question says "How much 0% solution was added?" We were already given that answer: 25 liters. Talk about a weird problem!
2007-01-31 13:00:13 · answer #1 · answered by Anonymous · 1⤊ 0⤋
This question makes no sense. If you mix a 0% solution with a 60% solution you will get something less than 60%, not more. So no mixture of the two can get you a 68% solution.
2007-01-31 21:48:35 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
Not possible if you mix a 60% solution & a 0% solution the resulting concentration c will be in the range of
2007-01-31 21:48:07
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answer #3
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answered by yupchagee 7
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