You need a common denominator
7(3x-2) 5(x+4)
--------- ---------
(x+4)(3x-2) (x+4)(3x-2)
21x-14 - (5x+20)
16x-34
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(x+4)(3x-2)
2007-01-31 12:34:16
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answer #1
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answered by leo 6
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You need to get a common denominator. Easiest way is to multiply the first fraction by (3x-2)/(3x-2) and the second fraction by (x+4)/(x+4). That will give you a common denominator of (x+4)(3x-2). Then distribute the tops and combine them - put them all over the messy denominator (which is now a quadratic).
2007-01-31 20:35:24
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answer #2
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answered by koolkat 3
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1. Solve > (7/x+4) - (5/3x-2)
First: find the Least Common Denominator (combine the denominators) which is, (x+4)(3x-2)...
Sec: multiply the denominators & corresponding numerators with the missing terms to get the L.C.D....
(3x-2)(7/x+4) - (x+4)(5/3x-2)
[7(3x-2)/(3x-2)(x+4)] - [5(x+4)/(3x-2)(x+4)]
*Use distribution with the numerators...
[7(3x) - 7(2)/(3x-2)(x+4)] - [5(x) + 5(4)/(3x-2)(x+4)]
(21x-14)/(3x-2)(x+4) - (5x+20)/(3x-2)(x+4)
Third: combine the numerators & keep them over the L.C.D...
[(21x-14) - (5x+20)]/(3x-2)(x+4)
[21x-14-5x-20]/(3x-2)(x+4)
(16x - 34)/(3x-2)(x+4)
Or, [2(8x-17)]/(3x-2)(x+4)
2007-01-31 20:41:44
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answer #3
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answered by ♪♥Annie♥♪ 6
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first u cross mutiply n u get 21x-14=5x+20
then u add 14 to both sides n u get 21x =5x+34
then you subtrct 5X from both sides and u get 17X=34
then u divide 17 by x and 34
then x=1
2007-01-31 20:39:19
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answer #4
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answered by mjbossy08 1
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(7(3x-2)-5(x+4))/(x+4)(3x-2)
(21x-14-5x-20)/((x+4)(3x-2))
16x-34/(x-4)(3x-2) or
2(8x-17)/(x-4)(3x-2)
2007-01-31 21:27:11
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answer #5
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answered by Anonymous
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16x+6
_________
(x+4)(3x-2)
2007-01-31 20:39:52
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answer #6
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answered by Sinead D 1
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7(3x-2)-5(x-4)
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(x+4)(3x-2)
21x-14-5x+20
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(x+4)(3x-2)
16x+6
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(x+4)(3x-2)
16x+6
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3x^2+10x-8
2007-01-31 20:40:49
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answer #7
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answered by brak_the_hun 3
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