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determine whether -4 satisfies each compound inequality. -3x>0 and 3x -4<11

2007-01-31 12:09:42 · 11 answers · asked by dan b 1 in Science & Mathematics Mathematics

11 answers

Can't you just substitue -4 in place of x in both equations? If both inequalities are true, job's a good'n.

2007-01-31 12:14:46 · answer #1 · answered by Gavin P 2 · 0 1

Ok, the way to solve this problem is simple; just substitute -4 for x and see if the inequalities are true.

a. -3x > 0
-3(-4) > ? 0
12 > 0 12 is greater than zero, so the result is correct

b. 3x - 4 < 11
-3(-4) - 4 12 - 4 8 < 11 8 is smaller than 11...so the result is correct

Good luck!

2007-01-31 12:16:41 · answer #2 · answered by alrivera_1 4 · 0 0

determine whether -4 satisfies each compound inequality. -3x>0 and 3x -4<11

In the first case we have 12>0 which is true
In the 2nd case we have -16<11 which is also true
Therefore -4 satisfies both inequalities.

2007-01-31 12:16:34 · answer #3 · answered by ironduke8159 7 · 0 0

all you have to do is plug in -4 into the question and then see if the inequality works

-3x>0
-3(-4) > 0
12>0 12 is greater then 0 so it works

3x-4<11
3(-4)-4<11
-12-4<11
-16<11 -16 is less then 11 so this also works

hope that was helpful

2007-01-31 12:13:52 · answer #4 · answered by MkP2o02 3 · 0 0

1) - 3x > 0

First: substitute "- 4" with the x-variable in the inequality...

- 3(-4) > 0

Sec: combine the values...

12 > 0
True

Third: yes --- the value "- 4" satisfies the inequality.

2) 3x - 4 < 11

First: substitute the value "-4" with the x-variable...

3(-4) - 4 < 11

Sec: combine the terms...

-12 - 4 < 11

- 16 < 11
True

Third: yes --- the value "- 4" satisfies the inequality.

2007-01-31 12:25:35 · answer #5 · answered by ♪♥Annie♥♪ 6 · 1 0

It satisfies the first one, because it would be 12>0.

Also, it satisfies the second one because -16<11 is true too

2007-01-31 12:13:52 · answer #6 · answered by Gerald 2 · 0 0

-3(-4) = 12; 12>0 TRUE
3(-4) - 4 = -16; -16 < 11 TRUE

It does.

2007-01-31 12:13:38 · answer #7 · answered by disposable_hero_too 6 · 0 0

plug in -4 for x: -3(-4) > 0. What's -3 time -4? Is it greater than 0?

2007-01-31 12:14:10 · answer #8 · answered by koolkat 3 · 0 2

Yes.

(-3)(-4) = 12 >0

3(-4) - 4 = -12 - 4 = -16 <11

Both are true.

2007-01-31 12:13:51 · answer #9 · answered by Northstar 7 · 0 0

Why can't you do this one buckwheat?

Plug in -4 for x and see if the equations remain true.

And there you have it, the answer is YES!

2007-01-31 12:15:43 · answer #10 · answered by Anonymous · 1 0

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