physics plz help?

Question

A golfer, standing on a fairway, hits a shot to a green that is elevated 4.72 m above where she is standing. If the ball leaves her club with a velocity of 49.0 m/s at an angle of 42.5 ° above the ground, find the time that the ball is in the air before it hits the green.

Answer 1

do 49sin42.5 to get y component of velocity. turns out to be 33.1m/s then find how high it gets and how long it takes to get there. use v^2=v^2+2as and v=v+at. s turns out to be 55.9 and t turns out to be 3.38. then find time it takes to go down the rest of the 51.18m use s=.5at^2+vit. t turns out to be 3.23. add to 3.38 to get 6.61 seconds.