find the probability of a drawing a club or an ace from a regular deck of playing cards.
answer 1: the answer is 17/52 since there are 13 clubs and 4 aces in a standard deck.
Answer 2: The answer is 4/52 because there are 4 aces in every standard deck
do you agree with either answer or do you have a different answer? explain how you solved this in words or in math
2007-01-31 12:06:48 · 9 answers · asked by andrew 3 in Science & Mathematics ➔ Mathematics
there are 52 cards in a deck
there are 13 clubs
there are 4 aces
since you want to find the probability of something happening OR something else happening, you will find the probability of each separate thing happening and then add them (if you wanted to find probability of something happening AND something else happening, you would multiply probabilities)
the probability of drawing a club is 13/52
the probability of drawing an ace is 4/52
13/52 + 4/52 is 17/52
so you would think you'd have a 17/52 chance of drawing an ace or a club
BUT
there is the ace of clubs. it's an ace, and it's a club. so if you said the probability was 17/52, you would have counted the ace of clubs twice, once as a club, and once as an ace. but there's only one card there!
so actually, the probability is 16/52, which reduces to 4/13
2007-01-31 12:15:14 · answer #1 · answered by branzillie 2 · 0⤊ 0⤋
There are 13 clubs in the pack including 1 of the aces. There are 3 other aces in the pack. Add these together and you have a 16 out of 52 chance of getting a club or an ace. You can simplify this down to 4 in 13 chance.
2007-01-31 12:22:51 · answer #2 · answered by Anonymous · 1⤊ 0⤋
in probability or means + so 4 aces 13 clubs = 17 so 17/52
2007-01-31 12:52:19 · answer #3 · answered by neo 2 · 0⤊ 0⤋
There are 13 Clubs in a deck: 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A
There are also Three additional aces: Ace(hearts), Ace (spades), Ace(diamands)
Probability if difined as:
Favorable Outcomes
---------------------------
Total Outcomes
Therefore, your answer is 16/52
2007-01-31 12:41:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
its 16/52 becasue you take the 13 clubs in the deck and the three other aces(one ace is already included as a club).
2007-01-31 12:11:14 · answer #5 · answered by guitar hero 2 · 1⤊ 0⤋
The probability of drawing an ace or a club is
p(A or Club) = 16/52
One of the clubs is an ace.
2007-01-31 12:12:11 · answer #6 · answered by Northstar 7 · 0⤊ 0⤋
a) In a typical deck of fifty two enjoying cards, there are 13 of each and every healthy. The danger that the 1st is a heart is 13/fifty two, or a million/4. This leaves a stack of fifty one enjoying cards, 13 of that are nonetheless golf equipment. So the wonderful answer is the made from (a million/4)(13/fifty one). i'm going to bypass away the simplifcation to you. b) only like till now, there's a a million/4 probabiltiy of drawing a diamond first. yet that leaves 12 diamonds in a stack of fifty two, so the respond is (a million/4)(12/fifty one) c) You advise selection or face, no longer healthy, good? no rely which card you p.c.., that's one in each and every of 13 denominations. There are 3 others like it left in the deck of fifty one enjoying cards, so the respond is 3/fifty one = a million/17.
2016-11-23 18:45:00 · answer #7 · answered by ? 4 · 0⤊ 0⤋
Your first answer sounds more reasonable since you also need to include clubs.....go with that one and good luck.
2007-01-31 12:12:32 · answer #8 · answered by Andrew H. 3 · 0⤊ 0⤋
uuuuuuuuuuuh.. what?
2007-01-31 12:10:11 · answer #9 · answered by bozomo99 1 · 0⤊ 2⤋