plz math wizards help me with probability this papers due tomarrow!!?

Question

a bag of yummy candy has 45 pieces. the candy comes in 4 colors:white, green, red, and blue. The probability of picking a white is 1/9, a red 1/5, and a green 1/3.

a bag of yummy minis has 5 fewer blue pieces than the bag of regular tummy candy. The number of the other pieces is the same. If you reach into the bag and take out one piece without looking, which piece will you most likely pick? plz show me how you got your answer

Answer 1

First you need to get everything in "like" terms with the big bag of candy, meaning that you make everything have the same denominator. You'll end up with:

White: 5/45
Red: 9/45
Green: 15/45

What do we have left? Blue. If the white, red, and green total 29/45, how many must be blue? 16. So, blue is 16/45.

Since there's 45 total candy pieces and and the denominator for each of the fractions is 45, this means that the numerator (the number on top of the fraction) will also work out to be the actual number of candies of that color. For example, there are 5 white candies, 9 red candies, 15 green candies, and 16 red candies.

Keep in mind that the higher the number of candies are for a certain color, the greater the probability that you'll pick one of them will be. So as it stands now, it's likely that you'll first pick a red, then a green, then a red, then a white. Do you see why?

Next, we'll eliminate 5 blue candies, since your question states that everything stays the same for the smaller candies except for 5 less blue ones.

Now our totals are:

White: 5 candies
Red: 9 candies
Green: 15 candies
Blue: 11 candies

Because the total number of candies is now 40 (because 45 - 5 = 40), to make these into fractions, we put 40 as the denominator, leaving:

White: 5/40
Red: 9/40
Green: 15/40
Blue: 11/40

Can you see which has the greatest probability of being picked now? It's green because there are more greens than any other candy. :)

I hope this helps and good luck with your probability paper!!!!

Answer 2

In the original bag: number of white pieces = (total number) * (probability of getting a white piece) = 45 * 1/9 = 5.
Similarly, there are 45 * 1/5 = 9 red pieces and 15 green pieces. So there are 45 - 5 - 9 - 15 = 16 blue pieces.

In the mini bag there are 11 blue pieces and the other numbers are the same, so the most likely selection is green which has 15 pieces.

Answer 3

white = 1/9, so there are 5 whites (1/9 * 45 pieces)
red = 1/5, so there are 9 reds
green = 1/3 so there are 15 greens

Since there are 45 total, there are 45 - (5+9+15) = 16 blues.

In the minis, you have 5 fewer blues, so only 11 blues. This also means there are only 40 pieces since the number of other pieces is the same.

So your mini ratios are:
blue = 11/40 = 2/5
white = 5/40 = 1/8
red = 9/40
green = 15/40 = 3/8

But we can tell which is most likely just by looking... there are more greem pieces than any other piece, so it is likely to be drawn first.

Hope this helps!

Answer 4

Normal bag: 45 pieces.

Green: 1/3 chance = 15 green pieces of 45
White: 1/9 chance = 5 white pieces of 45
Red: 1/5 chance = 9 red pieces of 45

15 + 5 + 9 = 29. 45 = 29 = 16 blue pieces.

Bag of minis: 40 pieces.
Green: 15/40 = 37.5% chance
White: 5/40 = 12.5% chance
Red: 9/40 = 22.5% chance
Blue: 11/40 = 27.5% chance

Assuming I read that correctly what with the 5 fewer blue pieces, you'll still have a higher chance of picking a green piece than a blue piece.