I need help with a 7th grade word problem?

Question

Here is the 1st one
A quality control engineer for a certain buyer found 2 defective parts in a sample of 50. At this rate, wat is the expected number of defective parts in a shipment of 50,000?

Please can somebody help me?

Answer 1

Very simple.


Here goes: 2 defective parts in a sample of 50... 2 out of 50...
2/50=1/25=4%.


Now, you know that 4% (0.04, in decimal form) of the parts are defective. Now simply multiply 0.04 by 50,000...
0.04*50,000=2,000 defective parts per 5,000. It's that simple.

Answer 2

Set up a proportion of the number of defective parts over the original number of parts to a number (x) over the problem's suggested number of parts. Or, you can multiply 50 until you get 50,000 (x 1000). Multiply 2 by the same number (1,000) to get the proposed number of defective parts in the sample of 50,000.

Peace

Answer 3

50/2=50000/x
cross multiply
solve for x

you should get 2,000 defective parts in a shipment of 50,000

Answer 4

2/50 = x/50,000
solve the equation
and you get: x = 2,000

so the final answer is 2,000 defective parts in a shipment of 50,000

Answer 5

Here follow this.
put 50/2=50000/x
then cross multiply
youll end up with 50x=100000
then divide 100000 by 50 you'll get 2000 defective parts

well hope that helps you =D

Answer 6

use ratios;
2 to 50 would be x to 50,000
2 x
_ = __

50 50,000
cross-multiply above:: (*-means multiply)
2*50,000=x*50

100000=x*50
now divide each side by 50
2000=x

the expected number is 2000

i hope this isnt too confusing!!!

Answer 7

it would be 2,000 defective parts out of 50,000.

Answer 8

Your using Yahoo to do your homework. I considered your questions and that's touching directly to the 6th one asking some math situation. If there is something you do no longer comprehend please ask your instructor. in line with threat in case you nonetheless don't comprehend get a practice? :(