Exponential functions are done before multiplication, so first do (x^2)^5=x^10. Then x^3*x^10=x^13.
2007-01-31 12:07:44
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answer #1
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answered by Orion 2
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the order of operations is PEMDAS
Parentheses, Exponents, Multiplication/Division, Addition/Subtraction
since you have parentheses around the x^2, you start there.
that's raised to the 5th power, an exponent, so you do that next
(x^2)^5 is x^10 (you multiply the exponents
then you multiply that answer by x^3
and you get x^13 (you add exponents)
2007-01-31 20:07:59
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answer #2
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answered by branzillie 2
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First (x^2)^5 is x^10 .Then you multiply x^3*x^10which gives you
x^13
2007-01-31 20:07:50
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answer #3
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answered by santmann2002 7
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*Use the method known as PEMDAS >>> (), exponents, multiplication, division, addition & subtraction....
First: you have x^2 raised to th 5th power --- when you have one base (x-variable) with two exponents > multiply exponents...
x^(2*5)
x^10
Sec: multiply the rest --- when you have two bases (x-variables) > add exponents...
(x^3)(x^10)
= x^13
2007-01-31 20:31:16
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answer #4
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answered by ♪♥Annie♥♪ 6
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multipli firt the numbers are inside the () go from in to out
2007-01-31 20:08:21
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answer #5
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answered by Anonymous
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start by powering what's in the parenthesis
then do it to the 5th power
and then times that by x^3
i think you get x^13
2007-01-31 20:08:35
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answer #6
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answered by Gerald 2
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Wow. People here ARE smart. If I ever have a real question, I'll just ask the math crew.
2007-02-01 01:14:39
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answer #7
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answered by 1K 6
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the answer is (x xor 3) times ((x xor 2) xor 5).
2007-01-31 20:11:40
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answer #8
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answered by sarah e 1
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