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where do you start the multiplying?

2007-01-31 12:00:50 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

Exponential functions are done before multiplication, so first do (x^2)^5=x^10. Then x^3*x^10=x^13.

2007-01-31 12:07:44 · answer #1 · answered by Orion 2 · 1 0

the order of operations is PEMDAS
Parentheses, Exponents, Multiplication/Division, Addition/Subtraction

since you have parentheses around the x^2, you start there.
that's raised to the 5th power, an exponent, so you do that next
(x^2)^5 is x^10 (you multiply the exponents
then you multiply that answer by x^3
and you get x^13 (you add exponents)

2007-01-31 20:07:59 · answer #2 · answered by branzillie 2 · 0 0

First (x^2)^5 is x^10 .Then you multiply x^3*x^10which gives you

x^13

2007-01-31 20:07:50 · answer #3 · answered by santmann2002 7 · 0 0

*Use the method known as PEMDAS >>> (), exponents, multiplication, division, addition & subtraction....

First: you have x^2 raised to th 5th power --- when you have one base (x-variable) with two exponents > multiply exponents...

x^(2*5)

x^10

Sec: multiply the rest --- when you have two bases (x-variables) > add exponents...

(x^3)(x^10)

= x^13

2007-01-31 20:31:16 · answer #4 · answered by ♪♥Annie♥♪ 6 · 0 0

multipli firt the numbers are inside the () go from in to out

2007-01-31 20:08:21 · answer #5 · answered by Anonymous · 0 1

start by powering what's in the parenthesis
then do it to the 5th power
and then times that by x^3

i think you get x^13

2007-01-31 20:08:35 · answer #6 · answered by Gerald 2 · 0 0

Wow. People here ARE smart. If I ever have a real question, I'll just ask the math crew.

2007-02-01 01:14:39 · answer #7 · answered by 1K 6 · 0 0

the answer is (x xor 3) times ((x xor 2) xor 5).

2007-01-31 20:11:40 · answer #8 · answered by sarah e 1 · 0 1

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