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heres the question- A 4 digit # is divisible by 5 but not 10. The tens digit is greater than 4 & is a power of 3. The hundreds digit is greater than 4 & is a power of 2. The thousands digit is less than 4 & is a power of 2 & 3. What is the #?

2007-01-31 11:59:19 · 5 answers · asked by . 2 in Science & Mathematics Mathematics

5 answers

1895

ones: we know it's a 5 because it is divisible by 5 but not 10.
tens: it's a power of 3, so it is 3 or 9. Since it has to be more than 4, it has to be a 9.
hundreds: it's a power of 2, so it is 2, 4, or 8. Since it's greater than 4, it has to be 8.
thousands: trick here... it's a power of both 2 and 3 AND it is less than 4. The only number that satisfies this is 1, since 2^0 and 3^0 both are 1.

Hope this makes sense!

2007-01-31 12:04:18 · answer #1 · answered by disposable_hero_too 6 · 0 0

i read this question like this. for a number to be a power of another number, say X, it has to be the value of X^n

for example 3, 9, are powers of three (3^1 = 3, 3^2 = 9)

so, let's say the number = abcd. for it to be divisible by 5 and not 10, d = 5

for the tens digit to be >4 and a power of 3, means c = 9

for the hundreds digit to be >4 and a power of 2 that means b is 8. (2^1 = 2, 2^2 = 4, 2^3 = 8)

for the thousands digit to be a power of 2 and 3, hmmmm what if the exponent is zero ie 2^0 and 3^0 ???

your number would be

a895 where a = 2^0 = 3^0

what's a?

2007-01-31 20:13:39 · answer #2 · answered by Dr W 7 · 0 0

1895

2007-01-31 20:46:44 · answer #3 · answered by ? 2 · 0 0

1895

2007-01-31 20:05:00 · answer #4 · answered by Om 5 · 0 0

yes, some people are good at math.

2007-01-31 20:13:54 · answer #5 · answered by sarah e 1 · 0 0

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