6x squared+4=0
2007-01-31 11:23:41 · 6 answers · asked by nisha10mabry 3 in Science & Mathematics ➔ Mathematics
6x^2 + 4= 0
6x^2 = -4
x^2= -2/3
there is no solution
if you use complex number
then x = sqr(2/3)i and -sqr(2/3)i
2007-01-31 11:32:24 · answer #1 · answered by 7 · 1⤊ 0⤋
Solve for X?
Subtract 4 from both sides.
6x^2=-4
Divide by 6.
x^2=-4/6 or -2/3
sqrt(x^2) = x = sqrt(-2/3)
Which is an imaginary number.
x = i * sqrt(-2/3)
OR (in decimals)
0.8164965809 i
2007-01-31 19:33:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
6x^2+4=0
6x^2+4-4=0-4
6x^2=-4
x^2=-4/6
x=-sqrt of-4/6
2007-01-31 19:42:29 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
6x^2+4=0
-4 -4
6x^2=-4
6x^2/6 =-4/6
x^2=-2/3
then square root each side...x=-.81
2007-01-31 19:32:28 · answer #4 · answered by hina s 2 · 0⤊ 0⤋
Undefined. It can't be solved.
2007-01-31 19:31:39 · answer #5 · answered by trueblue88 5 · 0⤊ 0⤋
do your own homework kid.
2007-01-31 19:31:29 · answer #6 · answered by Anonymous · 0⤊ 1⤋