The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply upward at the end. The sharp upward slope launches them into the air, where they perform acrobatic maneuvers. In the women's competition, the end of a typical launch ramp is directed 63° above the horizontal. With this launch angle, a skier attains a height of 10.2 m above the end of the ramp. What is the skier's launch speed?
2007-01-31 11:21:13 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
I made a mistake, the numbers above should be 63° and 12.5 m
thanks everyone for your help
2007-01-31 11:39:44 · update #1
oouch thatd be hard to work out
try looking on google to see if you can find any help or try sketching it
2007-01-31 11:26:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋
just use energy. in beginning its all kinetic, end its all potential. energy is conserved, so .5mv^2=mgh. m cancels out, so .5v^2=(9.8)(10.2). v turns out to be 14.14m/s
2007-01-31 11:32:39 · answer #2 · answered by climberguy12 7 · 0⤊ 0⤋