I heard it on the radio this morning, but I don't know if I heard it wrong. Is it true?
2007-01-31 11:11:01 · 15 answers · asked by Sarah 3 in Sports ➔ Baseball
Nope. Chase Utley recently resigned a big fat contract for the next 7 years at $85 million.
2007-01-31 17:51:52 · answer #1 · answered by davester1970 7 · 0⤊ 0⤋
Someone on the radio made a super boo boo! Utley's a Phil for years to come. Check out the links below.
2007-02-01 11:22:51 · answer #2 · answered by BloggingFool 2 · 0⤊ 0⤋
i'm not a Phillies fan, yet I envy that group! Utley is an incredible youthful participant, and that i strongly have faith (and desire) that they are going to end in front of the Mets in '07. The Phils have an impressive lineup & are relaxing to any authentic baseball fan. i'm greater of an AL West fan (avid) so sturdy success. Utley heavily isn't the "kiss of dying" for the Phillies in any respect. it may be the "kiss of dying" for the Mets.
2016-10-16 09:25:23 · answer #3 · answered by silvi 4 · 0⤊ 0⤋
No, he resigned with Philly for 85 million over 7 years
2007-01-31 11:53:29 · answer #4 · answered by Mr. Hole In One 2 · 0⤊ 0⤋
No he isn't. Utley will be a Phillie in 2007.
2007-02-02 10:28:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Nope Utley resigned with the Phils for 7 years and 85 million bucks...a bit more then I would wanna pay for him but he is a top 2B...
2007-01-31 11:51:57 · answer #6 · answered by kwann08 2 · 0⤊ 0⤋
no, he signed a 85 million 7 year deal with the phillies, new highest paid phillies record.
2007-01-31 12:07:00 · answer #7 · answered by luke 3 · 0⤊ 0⤋
You did hear it wrong.
He signed a big contract with the Phillies.
2007-01-31 11:39:46 · answer #8 · answered by Anonymous · 0⤊ 0⤋
It is false!! He signed a long term contract. Top second basemen in league. Have him on my fantasy league coming up this season. So draft him as a top second baseman OK!!!
2007-01-31 12:41:50 · answer #9 · answered by BoochBoy 2 · 0⤊ 0⤋
no, he sign with the phillies
2007-01-31 14:10:17 · answer #10 · answered by JESSIE 3 · 0⤊ 0⤋