running bear left the village and traveled 30 miles on a heading of 30 degrees. from this point he went 50 miles on a heading of 220 degrees. how far did he end up from the village?
2007-01-31 10:48:43 · 5 answers · asked by argentina_mandy20 1 in Science & Mathematics ➔ Mathematics
you should use Pythagorean theorem. A^2 + B^2 = C^2
30^2 + B^2 = 50^2
900 +B^2 = 2500
B^2=1600
B=40 miles
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2007-01-31 11:02:30 · answer #1 · answered by James O only logical answer D 4 · 0⤊ 0⤋
if you draw this out, you will see a triangle with one length of 30mi, one length of 50mi and an angle of 10 degrees between them. You need to use trigonometry to solve for the third side (opposite the 10 degree angle).
Hope this helps!
2007-01-31 10:56:45 · answer #2 · answered by disposable_hero_too 6 · 0⤊ 0⤋
Final destination= (30*cos(30)+50cos(220), 30sin(30)+50sin(220))=(-12.32,-17.14) distance =sqrt((-12.32)^2+(-17.4)^2)=21.11miles away from where he started.
2007-01-31 10:56:36 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋
80?
2007-01-31 10:57:05 · answer #4 · answered by westartednothing 2 · 0⤊ 0⤋
Too far. Lol.
2007-01-31 10:52:29 · answer #5 · answered by Anonymous · 1⤊ 1⤋