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Can you guys help me ?


You see I am having trouble with these complex questions like 56 X 12 = sum

I know how to multipliable single digit numbers with other single digit numbers. please refrain from any mocking. I am here to learn not to be some kind of a punching bag for someone else's problems thanks. I just want to know the process.

I also will like to know the dividing process with two or more digits as well as subtracting numbers by the take 1 next to the number way system. As you all could see I was not paying close attention in my low level course classes when I was young.

2007-01-31 10:20:40 · 2 answers · asked by TheMiddleisSafe 3 in Science & Mathematics Mathematics

2 answers

It is very difficult to explain these kind of arithmetic procedures in this type limited format. If you could find somebody who could review these techniques with you in person, it would probably be a lot easier to grasp.

I will go over the 56 x 12 manual multiplication process as a start. Adding and subtraction (by carrying a number from one column to the next or "borrowing" is even harder to show and probably should be put in a separate question to spread out the response effort)

First remember that the any number is represented by digits in columns that start with the "ones" column on the right, and then the "tens" column, then the "hundreds" column, etc.

The number 56 really means 5 tens and 6 ones.

To multiply 56 x 12 you would line them up, one on top of the other and due the multiplication digit by digit.

56
x 12
--------

Start with the 2 (in 12) and multiply it by the 6 (in 56), the result is 12. Remember that this 12 is actually 1 ten and 2 ones. Write the 2 in the ones column (the right most column) under the answer bar, and since the 1 part of the 12 you just calculated is a "tens" number, you put it in the "tens" column above the other "tens" digits in the problem:

1
56
x 12
-------
2

You have completed the first step, the 2 in twelve times the 6 in 56. Now you have to the 2 in twelve times the 5 in 56 (then you will move to the 1 in 12 and complete a similar set of steps.

The 2 (in 12) times the 5 (in 56) results in "10" but you have to add the 1 you carried from the first calculation so you get "11". (1 - hundred and 1-tens because it is really 2 * 50+10, the 5 being in the tens column and the one written at the top in the tens column). You write the "1" tens result in the tens column under the answer bar and you write the "1" hundreds result at the top of the problem like you did before, but in the correct column.

11
56
x 12
--------
12

There is nothing under the last one at the top so it is added to the nothing under it and so stays a one when you bring it down to the answer line.

11
56
x 12
--------
112

This seems like a lot of steps but it is pretty simple once you practice it a little bit. Now you have to do the 1 (in 12) times the 56. We first do 1 times the 6 and get 6. Since this is 1-ten, times 6-ones, the result is really "60" or 6 tens and goes in the tens column under the first-piece answer of 112. Then we multiply the 1 times the 5 (in 56) and get "5" which goes in the hundreds column next to the 6 we just wrote.

11
56
x 12
--------
112
56
---------

Now we just have to add our two "piece" answers to get the final answer. Many times this stage will require a knowledge of "carrying" to complete correctly. You have to know how to add large numbers in order to be able to multiply them. In this case their is no "carrying required because none of the column sums is over 10.

11
56
x 12
--------
112
56
---------
672

The answer is 672.
You can check that easily with a calculator or computer.

If you try this a few times with different numbers you may be able to start to catch the technique. Having somebody working with you would probably help a lot.

Also, math first, THEN multiplication, then subtraction, then division because the techniques build on each other.

Good luck
math is power

2007-01-31 10:48:22 · answer #1 · answered by enginerd 6 · 0 0

56
12
------
6X2 =12 the 2 goes under the line and you carry the 1 above the 5.

2X5=10+the one you carried=11 so one the first line underneath you have 112.

On the second line put a zero under the 2 in 112. Then 1X6 = 6 goes under the 2nd 1 in 112. That is a one digit number so nothing carries above the 5.
1X5 = 5 so the bottom line is 560.

Now the top line (112) plus the bottom line (560) = the answer (672)

2007-01-31 18:30:12 · answer #2 · answered by BC 2 · 0 0

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