Let u(t) be basic step function: u(t) = {0 if t< 0, 1 if 0<=t<=1, 0 if t >1} find the rule for u(3t+2)

Answer 1

3t+2<0 t<-2/3 u(3t+2) =0
3t+2<= 1 t<=-1/3 so if -2/3<=t<=-1/3 u(3t+2)=1
if t>-1/3 u(3t+2)=0